A balloon of mass 1 g has 100g of water in it. If it is completely immersed in water then what would be its mass:

0.5g

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1.0g

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2.0g

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101g

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Solution

The correct option is B 1.0g
Actual weight of 'balloon+water' in air $W = 1 + 100 = 101$ gf
Apparent weight of body in liquid W' = Actual weight - Weight of liquid displaced
$∴$ $W^{'} = (101) - 100 = 1$ gf
Thus its mass in water $m^{'} = 1.0$ gram

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A balloon of mass 1 g has 100g of water in it. If it is completely immersed in water then what would be its mass:

The correct option is B 1.0gActual weight of 'balloon+water' in air W=1+100=101 gfApparent weight of body in liquid W' = Actual weight - Weight of liquid displaced∴ W′=(101)−100=1 gfThus its mass in water m′=1.0 gram

The correct option is B 1.0g
Actual weight of 'balloon+water' in air $W = 1 + 100 = 101$ gf
Apparent weight of body in liquid W' = Actual weight - Weight of liquid displaced
$∴$ $W^{'} = (101) - 100 = 1$ gf
Thus its mass in water $m^{'} = 1.0$ gram