Question

# A balloon starts rising from the ground with an acceleration of $$1.25 \;ms^{-2}$$, After $$8$$ seconds, a stone is released from the balloon, The stone will $$(g=10\;ms^{-2})$$

A
cover a distance of 40 m in reaching the ground.
B
have a displaceent of 50 m
C
reach the ground in 4 second
D
begin to move down after being released

Solution

## The correct option is D reach the ground in 4 second$$s = \dfrac {1}{2} at^2$$$$a = 1.25\ m/s^2 \Rightarrow s = \dfrac {1}{2} \times 1.25 \times 8^2 = 40\ m$$After $$8\ sec$$ speed of balloon:$$v = u - gt$$$$v = -(1.25) \times 8 = - 10\ m/s$$Now, when stone is released distance to cover is $$40\ m$$.$$v^2 = u^2 - 2gs$$$$v^2 = (100)^2 + 2 \times 10 \times 40 \Rightarrow v = 30 m/s$$$$v = u - gt \Rightarrow - 30 = +10 - 10t$$$$t = 4\ s$$Physics

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