A balloon starts rising from the surface of the earth. The ascension rate is constant and equal to v0. due to the wind the balloon gather the horizontal velocity component v x=a y where is a constant and why is the height of ascent find the total tangential and normal acceleration of the balloon.?
The path of the balloon will look something like this
After t sec ballon would have gone a height of v0tthen at that very instance the balloon's vx will be
vx=av0t⇒ax=av0
Vy=v0
ay=0
ar=totalacceleration=av0.......(1)
vtangentical is actually the resultant velocity
⇒vt=√v20+(av0t)2
⇒vt=v0√1+a2t2