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Question

A balloonist is ascending at a velocity of 12 ms−1. A packet is dropped from it when it is at height of 65 m from the ground. Time taken by the packet to reach the ground is

A
5 s
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B
5 s
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C
7 s
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D
135 s
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Solution

The correct option is A 5 s
Using the second equation of motion,

s=ut+12at2

Here, s=65 m, u=12 m/s (since it's moving upwards), a=g=10 m/s2

65=12t+1210t2

5t212t65=0t=5;t=13/5
Since, time cannot be negative.
Thus, t=5s

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