Question

A bar AB of diameter 40 mm and 4 m long is rigidly fixed at its ends. A torque of 600 Nm is applied at a seciton of the bar. 1 m for end A. The fixing couples $T_{A}and{T}_B$ at the supports A and B, respectively, are

• A. 450 Nm and 150 N-m
• B. 200 Nm and 400 N-m
• C. 300 Nm and 150 N-m
• D. 300 Nm and 100 N-m

Answer 1

The correct option is A 450 Nm and 150 N-m

The angle of twist $\left(\theta \right)$ at the point of application of torque will be same for bar on both sides.

$Thus{T}_A{L}_A=T_B{L}_B$

$and{T}_A+T_B=T$

$T_A=\frac{T}{(1+\frac{L_A}{L_B})}=\frac{600}{(1+\frac{1}{3})}=450N-m$

$T_B=600-450=150N-m$