Question

A bar AB of diameter $45mm$ and $1m$ long is rigidly fixed at its ends. A torque of $100N-m$ is applied at a section of the bar, $625mm$ from end A. The fixing couples $T_A$ and $T_B$ at the supports A & B respectively, are:

• A. $16.5N-m,83.5N-m$
• B. $37.5N-m,62.5N-m$
• C. $62.5N-m,37.5N-m$
• D. $83.5N-m,16.5N-m$

Answer 1

The correct option is B $37.5N-m,62.5N-m$


We know that
$T_A=\frac{Tb}{a+b}$
$\Rightarrow T_A=\frac{100\times 375}{1000}=37.5N-m$
Similarly,
$T_B=\frac{Ta}{a+b}$
$\Rightarrow T_B=\frac{100\times 625}{1000}=62.5N-m$