Question

A bar is compressed to half of its original length, The magnitude of true strain produced in the deformed bar is (correct to two decimal places).

Answer 1

$L_0\to Initiallength$

$L=\frac{L_0}{2}\to Finallength$

$Truestrain,{ϵ}_T=ln\frac{L}{L_0}=ln\left(\frac{\left(\frac{L_0}{2}\right)}{L_0}\right)$
$=ln\frac{1}{2}=-0.693$

As the examiner mentioned "magnitude", only magnitude will be given 0.693.