A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle θ with the cross-section of the bar. If the area of cross-section be ‘A’, then when is the shearing stress maximum
A
θ=0∘
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B
θ=30∘
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C
θ=45∘
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D
θ=90∘
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Solution
The correct option is Cθ=45∘ Shearing stress =Fsin2θ2A. It will be maximum when sin2θ=maxi.e.sin2θ=1⇒2θ=90∘⇒θ=45∘.