A bar magnet falls with its north pole pointing down through the axis of a copper ring. When viewed from above, the current in the ring will be.
A
Clockwise while the magnet is above the plane of the ring and counter clockwise while below the plane of the ring
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B
Counter clockwise throughout
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C
Counter clockwise while the magnet is above the plane of the ring, and clockwise while below the plane of the ring
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D
Clockwise throughout
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Solution
The correct option is B Counter clockwise while the magnet is above the plane of the ring, and clockwise while below the plane of the ring When the bar is moved toward loop the flux will increase and the induced current will counter this flux.SO when the magnet is above the plane the direction of current will be counter clockwise.