A bar magnet freely falls along the axis of a copper loop. What can be said about the acceleration of the bar magnet when it comes near to the coil?

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Solution

Since the bar magnet is falling, there is a change in the magnetic field in the area taken by the coil. Hence, flux changes in the coil.

flux = B A
(where, B is magnetic field and A is area.)

Due to the change in the flux, emf is induced in the coil and by Lenz's law, current flows in the direction which opposes the change in the magnetic field.

So, force due to this current induced magnetic field opposes the motion of the bar magnet.

Therefore, net accelearation of the fall is less than acceleration due to gravity, g.

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