A bar magnet has a coercivity of 4×103Am−1. It is placed inside a solenoid of length 12 cm having 60 turns in order to demagnetize it, the amount of current that should be passed through the solenoid is:
Given: H=4×103 Am−1
L=12 cm
N=60
Bar magnet requires a magnetic intensity (H=4×103 Am−1) to become demagnetized.
Let n be the number of turns per unit length.
⇒n=NL=600.12=500 turns/metre
Now, H=nI
⇒I=Hn=4×103500=8 A