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Standard XII

Physics

Solenoid and Bar Magnet

A bar magnet ...

Question

A bar magnet of length 3 cm has points A and B along its axis at distances of 24 cm and 48 cm on the opposite sides. Ratio of magnetic fields at these points will be

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\frac{1}{2 \sqrt{2}}

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Solution

The correct option is A 8
Both points A and B lying on the axis of the magnet and on axial position
$B \propto \frac{1}{d^{3}} \Rightarrow \frac{B_{A}}{B_{B}} = {(\frac{d_{B}}{d_{A}})}^{3} = {(\frac{48}{24})}^{3} = \frac{8}{1}$

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A bar magnet of length 3 cm has points A and B along its axis at distances of 24 cm and 48 cm on the opposite sides. Ratio of magnetic fields at these points will be

The correct option is A 8Both points A and B lying on the axis of the magnet and on axial position B∝1d3⇒BABB=(dBdA)3=(4824)3=81

The correct option is A 8
Both points A and B lying on the axis of the magnet and on axial position
$B \propto \frac{1}{d^{3}} \Rightarrow \frac{B_{A}}{B_{B}} = {(\frac{d_{B}}{d_{A}})}^{3} = {(\frac{48}{24})}^{3} = \frac{8}{1}$