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Magnetisation

A bar magnet ...

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A bar magnet of magnetic dipole moment 10 Am^2 is in stable equilibrium the work done to rotate the magnet through 60 degree is l? The magnetic field is 0.2T

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Q. A magnetic dipole of dipole moment

M = 10 {Am}^{2}

is suspended at angle

45^{\circ}

in an external magnetic field of

\sqrt{2} \times 10^{- 5} T

. Find the work done by the magnetic field to bring the dipole moment to be in stable equilibrium ?

Q. A bar magnet is placed in the position of stable equilibrium in a uniform magnetic field of induction B. If it is rotated through an angle

180^{o}

, then the work is (M

=

magnetic dipole moment of bar magnet).

Q. The work done in rotating a bar magnet of magnetic moment

M

from its unstable equilibrium position to its stable equilibrium position in a uniform magnetic field

B

Q. A magnetic dipole of magnetic moment M is rotated through

360^{o}

in a magnetic field B.
The work done is

Q. A bar magnet is placed in the position of stable equilibrium in a uniform magnetic filed of induction B. If it is rotated through an angle

180^{\circ}

, then the work is: (M is magnetic dipole moment)

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