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Question

A bar magnet of moment of inertia I is vibrated in a magnetic field of induction 0.4×104T. The time period of vibration is 12 s. The magnetic moment of the magnet is 120 Am2. The moment of inertia of the magnet is (in kgm2) approximately:

A
2.1π2×102
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B
1.57×102
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C
1728×102
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D
172.8×104
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Solution

The correct option is C 172.8×104
An SHM takes place due to torque acting on magnet due to presence of magnetic field.
τ=μBsinθμBθ=Iω2θ
I=μBω2=μBT24π2
I=120×0.4×104×1224×π2
=172.8×104kgm2

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