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Standard XII

Physics

Shear Stress

A bar of cros...

Question

A bar of cross-section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angle $θ$ with a plane at right angles to the bar. Then shearing stress will be maximum if $θ$

0^{\circ}

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30^{\circ}

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45^{\circ}

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60^{\circ}

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90^{\circ}

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Solution

The correct option is C $45^{\circ}$
$S h e a r s t r e s s = \frac{F sin θ}{A / cos θ} = \frac{F sin 2 θ}{2 A}$
Shear stress will be maximum if $sin 2 θ = 1 o r 2 θ = 90^{\circ} i . e . θ = 45^{\circ}$

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A bar of cross-section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angle θ with a plane at right angles to the bar. Then shearing stress will be maximum if θ

The correct option is C 45∘Shearstress=FsinθA/cosθ=Fsin2θ2AShear stress will be maximum if sin2θ=1or2θ=90∘i.e.θ=45∘

A bar of cross-section A is subjected to equal and opposite tensile forces F at its ends. Consider a plane through the bar making an angle $θ$ with a plane at right angles to the bar. Then shearing stress will be maximum if $θ$

The correct option is C $45^{\circ}$
$S h e a r s t r e s s = \frac{F sin θ}{A / cos θ} = \frac{F sin 2 θ}{2 A}$
Shear stress will be maximum if $sin 2 θ = 1 o r 2 θ = 90^{\circ} i . e . θ = 45^{\circ}$