Question

A bar of varying square cross-section is loaded symmetrically as shown in the figure. Loads shown are placed on one of the axes of symmetry of cross-section. Ignoring self weight, the maximum tensile stress in $N/m{m}^2$ anywhere is

• A. $16.0$
• B. $20.0$
• C. $25.0$
• D. $30.0$

Answer 1

The correct option is C $25.0$

Tensile stress at $1-1=\frac{\text{Force}}{\text{Area}}$

$=\frac{250\times 1000}{100\times 100}=25N/m{m}^2$
Tensile stress at $2-2$
$=\frac{F}{A}=\frac{50\times 1000}{50\times 50}$
$=20N/m{m}^2$
Hence, max tensile stress = $25N/m{m}^2$