A barrel contains $n$ apples which are either red or white. If the probability of choosing a red apple is $70 %$ , then calculate the number of white apples.

\frac{3 n}{10}

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3 n

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\frac{10 n}{3}

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30 n

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\frac{100 n}{3}

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Solution

The correct option is A $\frac{3 n}{10}$
Given, Barrel contains $n$ apples which are either red or white
Probability of choosing red apple is $70 %$
So, no of red apples are $=$ $\frac{70}{100} \times n = \frac{7}{10} n$
Number of white apples will be $=$ $n - \frac{7}{10} n$
$\Rightarrow \frac{10 n - 7 n}{10} = \frac{3 n}{10}$

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A barrel contains n apples which are either red or white. If the probability of choosing a red apple is 70%, then calculate the number of white apples.

The correct option is A 3n10Given, Barrel contains n apples which are either red or whiteProbability of choosing red apple is 70%So, no of red apples are = 70100×n=710nNumber of white apples will be = n−710n⇒10n−7n10=3n10

A barrel contains $n$ apples which are either red or white. If the probability of choosing a red apple is $70 %$ , then calculate the number of white apples.