A base has kb=8.1×10^{-8} inwhat amount should 0.02 (m)HCland0.02(m)of BOH be mixed to make 200ml of a buffer of pH 7

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The base imidazole has $K_{b}$ of $1.0 \times 10^{- 7}$ . What volumes of 0.02 M HCl and 0.02 M imidazole should be mixed to make 150 mL of a buffer of pH 7 ?

The base imidazole has a $K_{b}$ of $9.8 \times 10^{- 8}$ at $25^{\circ}$ C.

In what ratio of volumes should 0.02 M HCl and 0.02 M imidazole be mixed to make 100 ml of a buffer at pH 7 ?

Q. If volume ratio of

0.02 M

H C l

and

0.02 M

B O H

(a weak base) mixed to make

200

mL of buffer of

p H = 7

2.23 : X

. The value of

X

is:

K_{b}

for

B O H = 8.1 \times 10^{- 8}

The base imidazole has a $K_{b}$ of $9.8 \times 10^{- 8}$ at $25^{\circ}$ C.

In what ratio of volumes should 0.02 M HCl and 0.02 M imidazole be mixed to make 100 ml of a buffer at pH 7 ?

The base imidazole has $K_{b}$ of $1.0 \times 10^{- 7}$ . What volumes of 0.02 M HCl and 0.02 M imidazole should be mixed to make 150 mL of a buffer of pH 7 ?

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