Question

A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises.

• A. 180 m
• B. 90 m
• C. 45 m
• D. 22.5 m

Answer 1

The correct option is C. 45 m.

Time taken to reach the maximum height = $\frac{6}{2}$ = 3 s

Final velocity, v = 0

Acceleration due to gravity = $g=-10m/s^2$

Using first equation of motion, v = u + at

0 = u - 10 $\times$ 3

u = 30 m/s

Now,

s = ut + $\frac{1}{2}a{t}^2$

s = 30 $\times$ 3 – $\frac{1}{2}$ $\times$ 10 $\times$ 3 $\times$ 3

Hence, s = 90 – 45 = 45 m.

Thus, the maximum height to which the ball rises is 45 m.