Question

A baseball player can throw a ball to a maximum distance of $60m$. He can throw it vertically to a maximum height of

• A. $10m$
• B. $30m$
• C. $60m$
• D. $100m$

Answer 1

Answer: (B)

$30m$

$R=\frac{v^{2}sin2\theta }{g}$
R is maximum at $\theta ={45}^o$
So, $\frac{v^2}{g}=60\Rightarrow v^2=60g.$

Now, for maximum height vertically,
$v^2=u^2-2gs$

At maximum height, $v=0$
$\Rightarrow s=\frac{u^2}{2g}=\frac{60g}{2g}=30m$