A basket contains apples, guavas and oranges. The number of guavas is $60 %$ more than that of apples and the number of oranges is $12.5 %$ less than that of Guavas. If the total number of these fruits is $80$ , then find the number of oranges.

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Solution

$y = 60 % o f x + x = \frac{60 x}{100} + x = \frac{16 x}{10} = \frac{8 x}{5}$

$z = y - \frac{125}{100} \times y$

$= y - \frac{y}{8}$

$= \frac{7 y}{8} = \frac{7}{8} \times \frac{8 x}{5} = \frac{7 x}{5}$
$x + y + z = 80$

$\Rightarrow x + \frac{8 x}{5} + \frac{7 x}{5} = 80$

$\Rightarrow x + \frac{15 x}{5} = 80$

$\Rightarrow 4 x = 80$

$\Rightarrow x = 20$

No. of oranges $= z$

$= \frac{7 x}{5}$

$= \frac{7}{5} \times 20$

$= 28$

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A basket contains apples, guavas and oranges. The number of guavas is 60% more than that of apples and the number of oranges is 12.5% less than that of Guavas. If the total number of these fruits is 80, then find the number of oranges.

y=60%ofx+x=60x100+x=16x10=8x5z=y−125100×y=y−y8=7y8=78×8x5=7x5x+y+z=80⇒x+8x5+7x5=80⇒x+15x5=80⇒4x=80⇒x=20No. of oranges =z=7x5=75×20=28

A basket contains apples, guavas and oranges. The number of guavas is $60 %$ more than that of apples and the number of oranges is $12.5 %$ less than that of Guavas. If the total number of these fruits is $80$ , then find the number of oranges.