Question

A basket holds n apples. You pick $(2n-3)$apples, and your friend picks $(n+4)$apples. How many apples do you and your friend pick together? How many baskets do you need to carry all the apples? Justify your answer.

Answer 1

As given:

The number of apples your friend picked $=n+4$

The number of apples you picked $=2n-3$

The number of apples you and your friend picked can be obtained by just adding the apples picked by both

$$\begin{gathered} =(2n-3)+(n+4) \\ =2n+n+4-3\{Commutativeproperty\} \\ =3n+1\{Combineliketerms\} \end{gathered}$$

The number of apples you and your friend picked is $3n+1$

Step 2: For carry $n$ apples basket required is = $1$

For carry $1$ apple basket required = $\frac{1}{n}$

For carry all $3n+1$ apples is $=\frac{1}{n}\times (3n+1)$