A bat flies perpendicularly towards a wall with a speed of 6 m/s, emitting sound of frequency 450 kHz. What is the frequency of the wave reflected from the wall that it will hear? Given, c=340 m/s.

422 KHz

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434 KHz

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466 KHz

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482 KHz

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Solution

The correct option is C
466 KHz

Here, the bat is the 'observer' and the 'image' is the source.
$n^{^{'}} = \frac{c - v_{0}}{c - v_{s}} \times n = [\frac{340 - (- 6)}{340 - 6}] 450 = 466 K H z$

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A bat flies perpendicularly towards a wall with a speed of 6 m/s, emitting sound of frequency 450 kHz. What is the frequency of the wave reflected from the wall that it will hear? Given, c=340 m/s.

The correct option is C 466 KHz Here, the bat is the 'observer' and the 'image' is the source. n′=c−v0c−vs×n=[340−(−6)340−6]450=466 KHz

The correct option is C
466 KHz

Here, the bat is the 'observer' and the 'image' is the source.
$n^{^{'}} = \frac{c - v_{0}}{c - v_{s}} \times n = [\frac{340 - (- 6)}{340 - 6}] 450 = 466 K H z$