A bat moving at 10ms−1 towards a wall sends a sound signal of 8000 Hz towards it. On reflection it hears a sound of frequency f. The value of f in Hz is close to (speed of sound =320ms−1)
A
8258
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B
8000
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C
8516
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D
8424
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Solution
The correct option is C 8516 the time taken relative to bat for sound wave to travel distance S between consecutive wave front traveling towards wall is T=SVsound/bat=18000 Vsound/bat=Vsound−Vbat T=SVsound−Vbat=18000...(i) After reflection as the bat is moving towards wall the time taken by sound to travel distance S is given as T′=SVsound+Vbat...(ii) substituting value of S from equation (i) in (ii) T′=Vsound−Vbat8000Vsound+Vbat...(iii) The apparent frequency will be f′=1T′ f′=Vsound+VbatVsound−Vbat8000 f′=10+320320−108000 f′=8516 Hz Hence correct answer is D.