Question

A batsman deflects a ball by an angle of ${45}^o$ without changing its initial speed which is equal to $54km/h$. what is the impulse imparted to the ball? (mass of the ball is $0.15kg$)

Answer 1

Velocity of ball $u=54km/h=54\times \frac{5}{18}=15m/s$

The ball struck by the bat is deflected back such that,

Total angle $={45}^0$

Now the initial momentum of the ball is $mucos\theta =\frac{0.15\times 54\times 1000\times cos22.5}{3600}$

$=0.15\times 15\times 0.9239$ along NO,

FInal momentum of the ball is $mucos\theta$ Along ON,

Thus Impulse is equal to the change in momentum,

$=mucos\theta -(-mucos\theta )=2mucos\theta =2\times 0.15\times 15\times 0.9239=4.16kgm/s$