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Question

# A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12ms−1. If the mass of the ball is 0.15 kg, determine the change in momentum of the ball. (Assume linear motion of the ball)

A
3.6kgm/s
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B
5kgm/s
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C
3.5kgm/s
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D
7kgm/s
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Solution

## The correct option is A 3.6kgm/sThe initial momentum of ball P1=m→v, after batsman hits ball and reverses its direction, momentum of ball P2=−m→vMagnitude of change in momentum Δp=|P2−P1|=|−2m→v|=2m|→v| from data given in question m=0.15kg;|→v|=12m/sΔP=2×0.15×12=3.6kgm/s

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