A battery connected to a pair of parallel 30 ohm resistor in series with a 9 ohm resistor. The current through the 9 ohm resistor is 0.25A. Find out the voltage applied to the circuit?
The equivalent resistance of pair of parallel 30 ohm resistor,
1R′=130+130
or R′=900/60=15Ω
now this equivalent resistance is in series with a 9 ohm resistor , so total resistance of the circuit ,
R=15+9=24Ω
given that ,current I=0.25A
therefore , voltage applied to circuit V=IR=0.25×24=6V