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Question
A battery of 9 V is connected in series with resistance of 0.2Ω, 0.3Ω, 5Ω, 0.5Ωand12Ω respectively. How much current would flow through the 12Ω resistor?
A battery of 9 V is connected in series with resistance of 0.2Ω, 0.3Ω, 5Ω, 0.5Ωand12Ω respectively. How much current would flow through the 12Ω resistor?
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Solution
The correct option is C 0.5A
Effective resistance = 18 ohm
Voltage = 9 V
I = 918 A = 0.5 A
0.5A
Effective resistance = 18 ohm
Voltage = 9 V
I = 918 A = 0.5 A
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