A battery of 9 V is connected in series with resistance of 0-2 - 0-3 - 5 - 0-5 - and 12 - respectively- How much current would flow through the 12 - resistor-A- 1 AB- 0-5 AC- 2 AD- 3 A

The correct option is B 0.5A Effective resistance = 18 ohm Voltage = 9 V I = 9/18 A = 0.5 A ...

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Standard X

Physics

Combination of Resistors

A battery of ...

Question

A battery of 9 V is connected in series with resistance of 0.2Ω, 0.3Ω, 5Ω, 0.5Ωand12Ω respectively. How much current would flow through the 12Ω resistor?

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0.5A

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Solution

The correct option is C
0.5A

Effective resistance = 18 ohm

Voltage = 9 V
I = $\frac{9}{18}$ A = 0.5 A

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A battery of 9 V is connected in series with resistance of 0.2Ω, 0.3Ω, 5Ω, 0.5Ωand12Ω respectively. How much current would flow through the 12Ω resistor?

The correct option is C 0.5A Effective resistance = 18 ohm Voltage = 9 V I = 918 A = 0.5 A

The correct option is C
0.5A

Effective resistance = 18 ohm

Voltage = 9 V
I = $\frac{9}{18}$ A = 0.5 A