Question

A battery of electromotive force $12V$ and internal resistance $2\Omega$ is connected to a resistor. If the current of $0.5A$ is flowing through the circuit then calculate the resistance of resistor. If the circuit is closed then what will be terminal voltage of the cell?

Answer 1

Using KVL,

$\epsilon =Ir+IR$

$12=0.5(2+R)$

$R=22\Omega$

Terminal voltage is:

$V=\epsilon -Ir=12-0.5\times 2=11V$