A battery of emf 15 V and internal resistance 2 ohm is connected to two resistor of 4 and 60 hms joined in series- Find electrical energy spent per minute in 6 o h m resistor-

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Standard X

Physics

Heating Effect of Current

A battery of ...

Question

A battery of emf 15V and internal resistance 2ohm is connected to two resistor of 4 and 6ohms joined in series.
Find electrical energy spent per minute in 6ohm resistor.

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Solution

EMF = 15 V
Total resistance in the circuit = 2 + 4 + 6 = 12 Ω
Current = I = 15/12 = 5/4 = 1.25 A

Energy in 1 min = Power * time duration
= I² R * T
= 5²/4² Α² * 6 Ω * 60 sec
= 562.50 Joules

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A battery of emf 15V and internal resistance 2ohm is connected to two resistor of 4 and 6ohms joined in series. Find electrical energy spent per minute in 6ohm resistor. ​

EMF = 15 V Total resistance in the circuit = 2 + 4 + 6 = 12 Ω Current = I = 15/12 = 5/4 = 1.25 A Energy in 1 min = Power * time duration = I² R * T = 5²/4² Α² * 6 Ω * 60 sec = 562.50 Joules

A battery of emf 15V and internal resistance 2ohm is connected to two resistor of 4 and 6ohms joined in series.
Find electrical energy spent per minute in 6ohm resistor.

EMF = 15 V
Total resistance in the circuit = 2 + 4 + 6 = 12 Ω
Current = I = 15/12 = 5/4 = 1.25 A

Energy in 1 min = Power * time duration
= I² R * T
= 5²/4² Α² * 6 Ω * 60 sec
= 562.50 Joules