Question

A battery of internal resistance $4\Omega$ is connected to the network of resistance as shown. In order to deliver the maximum power to the network, the value of R in ohm should be:

• A. $\frac{4}{9}$
• B. $2$
• C. $\frac{8}{3}$
• D. $18$

Answer 1

The correct option is B

$2$

For maximum power

Internal resistance = external resistance

$r=\frac{3R\times 6R}{(3R+6R)}\Rightarrow 4\Omega =2R\Rightarrow R=2\Omega$