A battery of internal resistance 4Ω is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of R (in Ω) should be
The equivalent network is
Clearly, the network of resistance is a balanced Wheatstone bridge .So RAE is given by
1RAE=13R+16R=2+16R=12R⇒ RAE=2R
For maximum power transfer 2R=4Ω ⇒ R=42=2Ω