A battery with an emf of $24 V$ is connected to a $6.0 Ω$ resistor $.$ As as result $,$ current $3.0 A$ exists in the resistor $.$ The terminal potential difference of the battery is $:$

18 V

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20 V

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25 V

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24 V

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Solution

The correct option is A $18 V$
$I = 3 A$
$R = 6 Ω$
$V = I R$
$= 3 \times 6 = 18 V$
Hence,
option $(A)$ is correct answer.

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A battery with an emf of 24V is connected to a 6.0Ω resistor. As as result, current 3.0A exists in the resistor. The terminal potential difference of the battery is:

The correct option is A 18VI=3AR=6ΩV=IR=3×6=18VHence,option (A) is correct answer.

A battery with an emf of $24 V$ is connected to a $6.0 Ω$ resistor $.$ As as result $,$ current $3.0 A$ exists in the resistor $.$ The terminal potential difference of the battery is $:$

The correct option is A $18 V$
$I = 3 A$
$R = 6 Ω$
$V = I R$
$= 3 \times 6 = 18 V$
Hence,
option $(A)$ is correct answer.