CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Potentiometer

A battery wit...

Question

A battery with negligible internal resistance is connected with 10m long wire. A standard cell gets balanced on 600 cm length of this wire. On increasing the length of potentiometer wire by 2m, the null point will be displaced by,

A

200 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

120 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

720 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

600 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 120 cm
By using $\frac{L_{1}}{L_{2}} = \frac{l_{1}}{l_{2}} \Rightarrow \frac{10}{12} = \frac{600}{l_{2}} \Rightarrow l_{2} = 720 c m$
Hence displacement = 720 – 600 = 120 cm

Suggest Corrections

thumbs-up

9

Similar questions

Q. A battery with negligible internal resistance is connected with 10m long wire. A standard cell gets balanced on 600 cm length of this wire. On increasing the length of potentiometer wire by 2m, the null point will be displaced by,

Q. A potentiometer wire of length

10 m

is connected in series with a battery. The e.m.f. of a cell balances against

250 c m

length of wire. If length of potentiometer wire is increased by

1 m

, the new balancing length of wire will be

Q. In fig. battery

E

55 c m

length of potentiometer wire but when a resistance of

10 o h m

is connected in parallel with the battery then it balances on

50 c m

length of the potentiometer wire then internal resistance

r

of the battery is

Q. A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of

2 V

and a negligible internal resistance. The potentiometer wire is

4 m

long. When the resistance

R = 9.5 Ω

is connected across a secondary cell the balancing length on the potentiometer wire was found to be

2.85 m

. If the balancing length for the emf of the secondary cell is

3 m

, the value of internal resistance of the cell is

10 m

long uniform metallic write having a resistance of

20 Ω

is used as a potentiometer wire. This wire is connected in series with another resistance of

480 Ω

and a battery of emf

5 V

having negligible internal resistance. If an unknown emf e is balanced across

6 m

of the potentiometer wire, calculate:
(i) The potential gradient across the potentiometer wire.
(ii) The value of the unknown emf e.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electrical Instruments

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon