CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A battle ship simultaneously fires two shells at enemy ships. Both are fired with the same speed but with different directions as shown. If the shells follow the parabolic trajectories shown, which ship gets hit first?


A

Need more information about the trajectories.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

They get hit at the same time.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

Ship μ1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Ship μ2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

They get hit at the same time.


Ship 2 gets hit first. The time of flight only depends on the y-component of motion, not the x-component. The higher you throw something up in the air, the more time it spends in the air. It can also be shown from equation-
y=v0y t - ½ g t2=0

v0y for projectile μ1 is greater than for μ2.


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centre of Mass in Galileo's World
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon