$a$ _ $b b a$ _ $b$ _ $a a b$ _ $a$ _ $b b a a b$ .

a a b b a

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b b a b a

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a a a a b

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a b a b a

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Solution

The correct option is B $a a b b a$
Here, the repitation is of $a a b b$
So, the series is $a a b b a a b b a a b b a a b b a a b$ .
Thus missing letters are $a a b b a$ .
Hence, option A is correct.

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