Find the value of velocity.
Given,
Mass of the bead, m=150 g
Radius, R=3 m
Natural length, L=1 m
Spring constant, k=316 N/m
Applying work-energy theorem between A and B,
Wg+Wstring=ΔK
mgh+12kx2=12mv2
150×10×31000+12×316×42=mv22
12=mv2
Find the value of normal.
N=mv2r
N=123=4 N
Final answer: 4