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Question

A bead of mass m is fitted on to a rod and can move on it without friction. Initially the bead is at the middle of the rod and the rod moves translationally in a horizontal plane with an acceleration ao in a direction forming an angle α with the rod. The downward acceleration of bead with respect to rod is
1189790_f1e09fa1b72d4da3997e305f21aca993.png

A
gsinα
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B
(g+a0)sinα
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C
gsinα+a0cosα
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D
gsinαa0cosα
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Solution

The correct option is D gsinαa0cosα
Let the mass of bed =m
Let the acceleration of bead =ab
Observing from the observer moving with rod
Then a pseudo force F=ma is applied on the bead in opposite direction of acceleration of rod
Now making FBD,
bead is not moving perpendicular to rod
N=mgcosαmasinα
Along the length of rod
Let the acceleration of rod along rod =ab
mgsinαmgcosα=mar
ar=gsinαacosα

1449002_1189790_ans_f5daf04fa77048aa8852a40ebcccc892.jpg

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