Question

A beaker containing a liquid of density $\rho$ moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is

• A. h $\rho$ g
• B. h $\rho$ (g-a)
• C. h $\rho$ (g+a)
• D. 2h $\rho$g $\left(\frac{g+a}{g-a}\right)$

Answer 1

Answer: (C)

h $\rho$ (g+a)

When a beaker containing a liquid of density $\rho$ moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift = (a+g)
$\therefore$ Pressure of liquid of height h = h $\rho$ (a+g)