Question

A beaker containing water is placed on the platform of a spring balance. The balance reads $1.5kg$. A stone of mass $0.5kg$ and density $500kg/m^3$ is immersed in water without touching the walls of beaker. What will be the balance reading now?

• A. $2kg$
• B. $2.5kg$
• C. $1kg$
• D. $3kg$

Answer 1

Answer: (B)

$2.5kg$

$Totalweight=W_{water}+F_B{W}_{water}=1.5g{F}_B=S_L{V}_g=S_L.\frac{m}{S_S}.g={10}^3\times \frac{0.5}{500}\times 1g=1g\therefore Totalweight=1.5g+g=2.5g\therefore Balancewillread2.5kg$