A beaker contains 200gm of water. The heat capacity of the beaker is equal to that of 20gm of water. The initial temperature of water in the beaker is 20∘C. If 440gm of hot water at 92∘C is poured into it, the final temperature od the system is
Let the final temperature of the system be T
Heat lost by hot water=Heat gained by cold water in beaker+Heat absorbed by beaker
or, (mcΔT)hot water=(mcΔT)cold water+(mcΔT)beaker
where, m is the mass of body, c is the specific heat of body and ΔT is the change in temperature of the body.
or, 440(92−T)=200×(T−20)+20×(T−20)
or, T=68∘C