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Question

A beaker contains 200gm of water. The heat capacity of the beaker is equal to that of 20gm of water. The initial temperature of water in the beaker is 20C. If 440gm of hot water at 92C is poured into it, the final temperature od the system is


A
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C
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D
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Solution

The correct option is B

Let the final temperature of the system be T

Heat lost by hot water=Heat gained by cold water in beaker+Heat absorbed by beaker
or, (mcΔT)hot water=(mcΔT)cold water+(mcΔT)beaker
where, m is the mass of body, c is the specific heat of body and ΔT is the change in temperature of the body.
or, 440(92T)=200×(T20)+20×(T20)
or, T=68C


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