A beaker contains 40g of water at 20?C. Now 50g of ice is put into the beaker . What is the final temperature of the mixture?

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Solution

Dear student,
$H e a t r e q u i r e d f o r m e l t i n g o f i c e t o w a t e r a t 0^{0} C = 50 \times 80 = 4000 J = 4 k J H e a t r e l e a s e d b y w a t e r a t 20 o C t o 0^{0} C = 40 \times 1 \times (20 - 0) = 800 J R e l e a s e d h e a t i s v e r y l e s s t h a n r e q u i r e d h e a t, s o f i n a l t e m p e r a t u r e w i l l b e 0^{0} C$

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A beaker contains 40g of water at 20?C. Now 50g of ice is put into the beaker . What is the final temperature of the mixture?

Dear student, Heat required for melting of ice to water at 00C=50×80=4000J=4kJ Heat released by water at 20 o C to 00C=40×1×(20−0)=800J Released heat is very less than required heat, so final temperature will be 00C Regards