A beaker of circular cross-section of radius 5cm is filled with mercury upto a height of 15cm. Find the force exerted by the mercury on the bottom of the beaker. Take atmospheric pressure =105N/m2, density of mercury =13600kg/m3, and g=10m/s2.
A
9425N
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B
942.5N
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C
94.25N
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D
785.4N
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Solution
The correct option is B942.5N Atmospheric pressure, Po=105N/m2 The pressure at the bottom, P=Po+ρgh ⇒P=105+13600×10×0.15 ⇒P=1.2×105N/m2 ∴ The force exerted by the mercury on the bottom is F=PA ⇒F=1.2×105×π×(0.05)2 ⇒F=942.5N