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Question

A beaker of circular cross-section of radius 5 cm is filled with mercury upto a height of 15 cm. Find the force exerted by the mercury on the bottom of the beaker. Take atmospheric pressure =105 N/m2, density of mercury =13600 kg/m3, and g=10 m/s2.

A
9425 N
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B
942.5 N
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C
94.25 N
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D
785.4 N
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Solution

The correct option is B 942.5 N
Atmospheric pressure, Po=105 N/m2
The pressure at the bottom,
P=Po+ρgh
P=105+13600×10×0.15
P=1.2×105 N/m2
The force exerted by the mercury on the bottom is
F=PA
F=1.2×105×π×(0.05)2
F=942.5 N

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