MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Acceleration Due To Gravity

A beaker of l...

Question

A beaker of liquid accelerates from rest, on a horizontal surface, with acceleration $a$ to the right.
How does the pressure vary with depth below the surface?

Open in App

Solution

$P = P_{0} + ρ g h$
where $h$ is the depth

Suggest Corrections

thumbs-up

0

Similar questions

Q. A beaker of liquid accelerates from rest, on a horizontal surface, with acceleration

a

to the right.
Which edge of the water surface is higher?

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration

^{'} a^{'}

. The pressure in the liquid at a depth

h

below the free surface of the liquid is (consider atmospheric pressure to be

P_{0}

)

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration

^{'} a^{'}

. The pressure in the liquid at a depth

h

below the free surface of the liquid is (consider atmospheric pressure to be

P_{0}

)

Q. The tension in a string holding a solid block of density

ρ_{S}

below the surface of a liquid of density

ρ_{l} (ρ_{l} > ρ_{S})

T_{0}

when the beaker is at rest. Tension in the string when beaker moves up with acceleration

a

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

PHYSICS

Watch in App

explore_more_icon

Explore more

Acceleration Due To Gravity

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon