Question

A beam (El = constant) of span L is subjected to clockwise moments M at both the ends A and B. The rotation of end A works out to be

• A. $\frac{ML}{2EI}$
• B. $\frac{ML}{3EI}$
• C. $\frac{ML}{4EI}$
• D. $\frac{ML}{6EI}$

Answer 1

The correct option is D $\frac{ML}{6EI}$

Rotation at A due to moment
at A =$\frac{ML}{3EI}$

Rotation at A due to moment at $B=-\frac{ML}{6EI}$

$\therefore RotationatA=\frac{ML}{6EI}$