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Strength of Materials

Moment Area Theorem

A beam El = c...

Question

A beam (El = constant) of span L is subjected to clockwise moments M at both the ends A and B. The rotation of end A works out to be

A

\frac{M L}{2 E I}

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B

\frac{M L}{3 E I}

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C

\frac{M L}{4 E I}

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D

\frac{M L}{6 E I}

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Solution

The correct option is D $\frac{M L}{6 E I}$
Rotation at A due to moment
at A = $\frac{M L}{3 E I}$

Rotation at A due to moment at $B = - \frac{M L}{6 E I}$

$∴ R o t a t i o n a t A = \frac{M L}{6 E I}$

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