Question

A beam has a triangular cross-section having base 40 mm and altitude 60 mm. If this section is subjected to a shear force of 36000 N, the maximum shear stress in the cross-section would be

• A. $60N/m{m}^2$
• B. $36N/m{m}^2$
• C. $45N/m{m}^2$
• D. $30N/m{m}^2$

Answer 1

The correct option is C $45N/m{m}^2$

The average shear stress, ${\tau }_{av}=\frac{V}{\left(bh/2\right)}$

$\therefore {\tau }_{av}=\frac{36000}{(40\times 60/2)}=30N/m{m}^2$

$\therefore$ Maximum shear stress $=1.5{\tau }_{av}$

$=45N/m{m}^2$