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Question

A beam made of steel is shown in figure. At collapse, the value of P is kMPL. The value of k, (rounded off to two decimal place) is ______

  1. 4

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Solution

The correct option is A 4
Redundancy, r = 5 - 3 = 2

No. of hinges for collapse = 2 + 1 = 3

(i) Span AB
Hinges form at A, B and at mid span
From the principle of virtual work

2MPθ+2MP(2θ)+MPθ=12×Lθ2×L×(PL)

7MPθ=PLθ4P=28MPL

(ii) Span BC
MPθ+MP(2θ)=PLθ2P2Lθ2

P=12MPL

(iii) Span CD

MPθ=P2.L2θ

P=4MPL

Collapse load, min of
(4MPL,12MPL,28MPL)
=4MPL

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