A beam of electrons has an energy of 1 joule.How many electrons are in the beam? (1 eV= 1.6*10^-19).

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Solution

$E n e r g y, E = n h v = e V E = 1 \times 1.6 \times 10^{- 19} = 1.6 \times 10^{- 19} e V N o . o f e l e c t r o n = 1$

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A beam of electrons has an energy of 1 joule.How many electrons are in the beam? (1 eV= 1.6*10-19).

Energy,E=nhv=eVE=1×1.6×10-19=1.6×10-19eVNo. of electron=1

A beam of electrons has an energy of 1 joule.How many electrons are in the beam? (1 eV= 1.6*10^-19).

$E n e r g y, E = n h v = e V E = 1 \times 1.6 \times 10^{- 19} = 1.6 \times 10^{- 19} e V N o . o f e l e c t r o n = 1$